ADD a new levenshtein matrix calculation.

pull/7/head
JKamlah 6 years ago
parent 29a2c8218f
commit 6ad003b015

@ -16,26 +16,36 @@ def levenshtein_matrix(seq1, seq2):
This algorithm is implemented here because we need an implementation that can work with sequences other than
strings, e.g. lists of grapheme clusters or lists of word strings.
"""
m = len(seq1)
n = len(seq2)
def from_to(start, stop):
return range(start, stop + 1, 1)
D = np.zeros((m + 1, n + 1), np.int)
D[0, 0] = 0
for i in from_to(1, m):
D[i, 0] = i
for j in from_to(1, n):
D[0, j] = j
for i in from_to(1, m):
for j in from_to(1, n):
D[i, j] = min(
D[i - 1, j - 1] + 1 * (seq1[i - 1] != seq2[j - 1]), # Same or Substitution
D[i, j - 1] + 1, # Insertion
D[i - 1, j] + 1 # Deletion
)
# Generate unique grapheme sets for both sequences
seq1set = set(seq1)
seq2set = set(seq2)
# All grapheme which occur in both sets
interset = seq1set.intersection(seq2set)
# Generate a boolean-mask for each interset grapheme
masks = {grapheme:[1]*(len(seq2)+1)for grapheme in interset}
for idx, grapheme in enumerate(seq2):
if grapheme in interset:
masks[grapheme][idx] = 0
D = np.ones((m + 1, n + 1), np.int)
D[:,0] = np.arange(m+1)
D[0,:] = np.arange(n+1)
for row, grapheme in enumerate(seq1):
if seq1[row] in interset:
mask = masks[grapheme]
for col in range(0,n):
D[row + 1, col + 1] = min(D[row, col] + mask[col], D[row + 1, col]+1, D[row, col + 1]+1)
else:
for col in range(0,n):
D[row+1,col+1] = min(D[row,col],D[row+1,col],D[row,col+1])+1
return D

Loading…
Cancel
Save